so you know the roll of one of the dice is a three

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OpenStudy (julie):

looks to me there are 3 options that get you odd, 3 that give you even

OpenStudy (julie):

in sum

OpenStudy (julie):

(so 3/6 possibilities for the second die to make an odd number) = 50%

OpenStudy (anonymous):

ohhhhh ok i get it

OpenStudy (julie):

that's generally how these work - you want to consider <success case>/<total possibilities> - especially given all possibilities are equally likely e.g. a fair die

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OpenStudy (anonymous):

oh wow i wish my teacher would have put it that way