so you know the roll of one of the dice is a three
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OpenStudy (julie):
looks to me there are 3 options that get you odd, 3 that give you even
OpenStudy (julie):
in sum
OpenStudy (julie):
(so 3/6 possibilities for the second die to make an odd number) = 50%
OpenStudy (anonymous):
ohhhhh ok i get it
OpenStudy (julie):
that's generally how these work - you want to consider <success case>/<total possibilities> - especially given all possibilities are equally likely e.g. a fair die
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OpenStudy (anonymous):
oh wow i wish my teacher would have put it that way