Mathematics
OpenStudy (anonymous):

20 pounds of a salt water solution contains 15 percent salt ,how much water must be added to weaken thesolution to 12percent salt?

So let's figure out first how much salt is in the water. If we have 20 pounds of salt water, and 15 percent of it is salt, we can find the amount of salt in the water by saying: $$0.15 * 20 = 3$$ So 3 pounds are salt and 17 pounds are water. Then we need 12 percent salt. We can set up an equality: $$\frac{3}{w} = \frac{12}{100}$$

There, $$w$$ is the amount of salt water (i.e., the total). We're saying 12 out of 100 is the same as 3 pounds out of how many total pounds. 12 out of 100 is because 12% is defined as 12 parts out of every 100. Does that make sense? Is that enough for you to find the answer?

OpenStudy (anonymous):

thank you it does :)

Awesome! :)

OpenStudy (anonymous):

:)

Latest Questions
dukedadon: i hope everyone's day is going well :D
2 minutes ago 17 Replies 1 Medal
TETSXPREME: Help
41 seconds ago 9 Replies 1 Medal
KamieQueen: Are soul mates a real thing?
5 minutes ago 10 Replies 2 Medals
KamieQueen: Did we invent math or did we discover it?
11 minutes ago 11 Replies 3 Medals
Darfangel: Which planets are most like Earth? Which are most different from Earth
10 minutes ago 8 Replies 4 Medals
Knockout3000: I need this for science! Read the PDF carefully!
40 minutes ago 6 Replies 0 Medals