Ask your own question, for FREE!
Mathematics 35 Online
OpenStudy (anonymous):

givne a matrix A m by n.....there exist matrices C and D such that such that cA = I of n by n and AD = I m by m prove that C=D and m =n

OpenStudy (anonymous):

the problem is one of inverse matrices. given \[AA^{-1} = A^{-1}A=I_x\] where x is the dimension of a square matrix, the rest should follow

OpenStudy (anonymous):

Suppose A is an m n matrix and there exist matrices C and D such that CA = In and AD = Im. Prove that m = n and C = D.

OpenStudy (anonymous):

\[X_{mn}Y_{kl}=Z_{ml}\] and \[n=m\] for any matrices X,Y Since \[I_n\] is a square matrix \A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

OpenStudy (anonymous):

\[A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

OpenStudy (anonymous):

sorry, and \[n=k\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
AsianPanda08: Does anyone know how to change the background of this?
8 minutes ago 2 Replies 0 Medals
curriful: Black QuestionCove Theme (WIP)
5 hours ago 19 Replies 1 Medal
Nina001: How do I make an image my background
12 hours ago 0 Replies 0 Medals
EdwinJsHispanic: imma sing notion
17 hours ago 13 Replies 0 Medals
EdwinJsHispanic: another song for someone
17 hours ago 66 Replies 5 Medals
MakaylaChuck23: I need tips on how to expand my English vocabulary
21 hours ago 13 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!