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OpenStudy (anonymous):

givne a matrix A m by n.....there exist matrices C and D such that such that cA = I of n by n and AD = I m by m prove that C=D and m =n

OpenStudy (anonymous):

the problem is one of inverse matrices. given \[AA^{-1} = A^{-1}A=I_x\] where x is the dimension of a square matrix, the rest should follow

OpenStudy (anonymous):

Suppose A is an m n matrix and there exist matrices C and D such that CA = In and AD = Im. Prove that m = n and C = D.

OpenStudy (anonymous):

\[X_{mn}Y_{kl}=Z_{ml}\] and \[n=m\] for any matrices X,Y Since \[I_n\] is a square matrix \A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

OpenStudy (anonymous):

\[A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

OpenStudy (anonymous):

sorry, and \[n=k\]

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