OpenStudy (anonymous):

givne a matrix A m by n.....there exist matrices C and D such that such that cA = I of n by n and AD = I m by m prove that C=D and m =n

7 years ago
OpenStudy (anonymous):

the problem is one of inverse matrices. given $AA^{-1} = A^{-1}A=I_x$ where x is the dimension of a square matrix, the rest should follow

7 years ago
OpenStudy (anonymous):

Suppose A is an m n matrix and there exist matrices C and D such that CA = In and AD = Im. Prove that m = n and C = D.

7 years ago
OpenStudy (anonymous):

$X_{mn}Y_{kl}=Z_{ml}$ and $n=m$ for any matrices X,Y Since $I_n$ is a square matrix \A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

7 years ago
OpenStudy (anonymous):

$A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n$

7 years ago
OpenStudy (anonymous):

sorry, and $n=k$

7 years ago