Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

givne a matrix A m by n.....there exist matrices C and D such that such that cA = I of n by n and AD = I m by m prove that C=D and m =n

OpenStudy (anonymous):

the problem is one of inverse matrices. given \[AA^{-1} = A^{-1}A=I_x\] where x is the dimension of a square matrix, the rest should follow

OpenStudy (anonymous):

Suppose A is an m n matrix and there exist matrices C and D such that CA = In and AD = Im. Prove that m = n and C = D.

OpenStudy (anonymous):

\[X_{mn}Y_{kl}=Z_{ml}\] and \[n=m\] for any matrices X,Y Since \[I_n\] is a square matrix \A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

OpenStudy (anonymous):

\[A_{mn}C_{xy}=I_{n} \quad n=x,\text { and }m=y=n \]

OpenStudy (anonymous):

sorry, and \[n=k\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
jmahoney: ya'll gonna do an update?
13 minutes ago 7 Replies 0 Medals
14xavierrobinson: what is discrimination
3 hours ago 1 Reply 0 Medals
quasia: Who were the members of each alliance in World War I?
3 hours ago 5 Replies 1 Medal
Vocaloid: AP Calc BC Study Guide/Tutorial
3 hours ago 1 Reply 7 Medals
NoProbBob: Help Yo SS below
3 hours ago 15 Replies 1 Medal
yallbabynene08: help
2 hours ago 20 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!