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OpenStudy (anonymous):
diff eq [sin(xy)+xycos(xy)+2x]dx+[x^2cos(xy)+2y]dy=0
8 years ago
OpenStudy (anonymous):
hey dy/dx=-[sin(xy)+xycos(xy)+2x]/[x^2cos(xy)+2y] thats it you dont have to take derivatives.
8 years ago
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