how do you find the first derivative of p=4 + x^2 all over 4 - x^2
\[p=(4+x^2)/4-x^2=1+1/4x^2-x^2=1-3/4x^2\] \[p \prime=-3/4*2*x=-3x/2\] i hope i didn't do any mistake
this is incorrect: if the original equation is: \[(4 + x^2) / (4 - x^2)\]
you can consider this as \[4/(4-x^2) + (x^2)/(4-x^2)\]
dad0gg, can we get some more clarification when you get back here?
Join our real-time social learning platform and learn together with your friends!