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y^-2-3y^-1+4
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4/Y+2+3Y
That isn't the answer...
what're you trying to do here, live4missions?
\[y^2-3*y^-1+4 = y^2 - 3*(1/y) + 4\]
I'm trying to solve for y, when the equation is equal to 0
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suppose \[y^{-1}=t\] then \[y^{-2}=t^{2}\] , and you will be able to solve this equation...
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