For what value k are the graphs y= -1 over 2 x+ 6 and 4y - kx =-28
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ARe the graphs what...? equal?
y=-(1/2) x +6
Is this the first equation? or is it y=-1/(2x+6)
I am going to assume you meant the first equation above and if that is the case then the slopes must be negative reciprocals if they are perpendicular. So set each equation y=...and then set the slope of one equal to the negative reciprocal of the other. solving it this way then k=-8