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OpenStudy (megan):

how do you solve sectheta/csctheta

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OpenStudy (megan):

anyone?

OpenStudy (anonymous):

have you converted these into their equivalent e functions?

OpenStudy (anonymous):

oops are you referring to hyperbolics? maybe not. If not just use your trig identities and simplify sec / csc

OpenStudy (mack):

hey shadowfiend come to the chat and let us chat

OpenStudy (anonymous):

you could do it with e functions as sin(x) = (e^(ix)-e^(-ix)) / (2i), but this isn't a very pretty way to solve it. Use your 1/Cos(x) = Sec(x) and 1/Sin(x) = Csc(x), then see if you recognize the new quotient...

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