Ask your own question, for FREE!
Mathematics 39 Online
OpenStudy (anonymous):

y dx + (2xy - e^(-2y) dy) = 0 solve using integrating factor

OpenStudy (anonymous):

Divide by dy then y and rearrange: x'+2x=e^(-2y)/y Integrating factor: e^integral(2dy) = e^(2y) (x*e^(2y))' = e^(2y)*e^(-2y)/y = 1/y Integrate: x*e^(2y) = ln(y) + c Solution: x(y) = (ln(y) + c) * e^(-2y)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
ImBOB: How is your day be honest
2 hours ago 4 Replies 2 Medals
rose12345: helppppppppppp
5 hours ago 1 Reply 0 Medals
yomomalikebracobama: help english
6 hours ago 3 Replies 2 Medals
supie2: anyone wanna help me
9 hours ago 6 Replies 0 Medals
yomomalikebracobama: halp more more
10 hours ago 9 Replies 4 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!