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OpenStudy (anonymous):
How do I solve for r in w=Cr^-2?
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OpenStudy (anonymous):
w = Cr^-2 w = C / r^2 (r^2)(w) = C r^2 = w / C sqrt (r^2) = sqrt (w/C) r = +/- sqrt (w/C)
OpenStudy (anonymous):
Thank you very much!
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