Ask
your own question, for FREE!
Mathematics
52 Online
curvature of y=sin(x) at x=pi/4
Still Need Help?
Join the QuestionCove community and study together with friends!
So if y = f(x) = sin x, then f'(x) = cos x and f''(x) = -sin x. This gives k = | -sin x | / [ 1 + (cos x)^2 ]^(3/2) for the curvature at the point x. For x = pi/4, we have that sin pi/4 = cos pi/4 = 1/sqrt(2). So the curvature at the point x=pi/4 is given by: k = (1/sqrt(2) ) / [ 1 + 1/2 ]^(3/2) = 2/ ( 3*sqrt(3) )
Oooh! Thanks!
You are welcome :)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
na2006x:
1,200 employees of a company were surveyed to find out whether they were satisfied with the companyu2019s insurance policy.
bestguy:
Eye Level poem The world looms large, a towering stage, Where giants stride and stories rage.
singlelesbain15:
Thought about this poem how do you guys like it TRAPPED Depression is like a dark
willowjade:
wrote this last night lmk what you think She just wanted to feel pretty. Sure she was called pretty by her parents.
7 hours ago
5 Replies
1 Medal
7 hours ago
9 Replies
2 Medals
10 hours ago
5 Replies
2 Medals
10 hours ago
23 Replies
5 Medals