Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

curvature of y=sin(x) at x=pi/4

OpenStudy (anonymous):

So if y = f(x) = sin x, then f'(x) = cos x and f''(x) = -sin x. This gives k = | -sin x | / [ 1 + (cos x)^2 ]^(3/2) for the curvature at the point x. For x = pi/4, we have that sin pi/4 = cos pi/4 = 1/sqrt(2). So the curvature at the point x=pi/4 is given by: k = (1/sqrt(2) ) / [ 1 + 1/2 ]^(3/2) = 2/ ( 3*sqrt(3) )

OpenStudy (anonymous):

Oooh! Thanks!

OpenStudy (anonymous):

You are welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos: ik i'm late but finished ToT added some details :p
2 hours ago 2 Replies 0 Medals
Grimson: What's your new years resolution.
8 hours ago 1 Reply 1 Medal
LemmyluvsGelo: Why be sad when you could js be Gone . ud83dudd7a
7 hours ago 4 Replies 1 Medal
Ferrari: anyone have insta??
3 hours ago 23 Replies 3 Medals
xXAikoXx: I made art
12 hours ago 6 Replies 3 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!