Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

curvature of y=sin(x) at x=pi/4

OpenStudy (anonymous):

So if y = f(x) = sin x, then f'(x) = cos x and f''(x) = -sin x. This gives k = | -sin x | / [ 1 + (cos x)^2 ]^(3/2) for the curvature at the point x. For x = pi/4, we have that sin pi/4 = cos pi/4 = 1/sqrt(2). So the curvature at the point x=pi/4 is given by: k = (1/sqrt(2) ) / [ 1 + 1/2 ]^(3/2) = 2/ ( 3*sqrt(3) )

OpenStudy (anonymous):

Oooh! Thanks!

OpenStudy (anonymous):

You are welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!