Ask
your own question, for FREE!
Mathematics
56 Online
y=2+(1/x-3) lim x ->0 and infinitive I got the answer = 1.6 and infinitive. it is continuous. is this right?
Still Need Help?
Join the QuestionCove community and study together with friends!
is a bit unclear. y = 2 + [1/(x - 3)]?
yea
the function \[y =2 + [1/(x-3)]\] is a rational function, so it's continuous only when it's denominator doesn't equal 0. (x-3) equals 0 if x = 3. Since you're looking for the limit as x-> 0, and x is continuous at that point, you can directly plug in the 0 into the equation, getting: 2+(1/0-3)) = 2+ -1/3 = 5/3. So the limit as x-> 0 of the function is 5/3.
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
ShinePrincess:
Write a function that will create the following transformation. Shift f(x) down 3
forgetmylife:
Only the real understand ud83eudd26ud83cudffdu2642ufe0f I'm tired. Tired of the constancy, the constancy of judgment.
rishavraj:
Just trying to find a friend. We met on openstudy, her nickname on there was something "tarantula".
41 minutes ago
0 Replies
0 Medals
10 hours ago
2 Replies
1 Medal
1 hour ago
4 Replies
0 Medals