Ask your own question, for FREE!
Mathematics
OpenStudy (kelly):

y=2+(1/x-3) lim x ->0 and infinitive I got the answer = 1.6 and infinitive. it is continuous. is this right?

OpenStudy (anonymous):

is a bit unclear. y = 2 + [1/(x - 3)]?

OpenStudy (kelly):

yea

OpenStudy (anonymous):

the function \[y =2 + [1/(x-3)]\] is a rational function, so it's continuous only when it's denominator doesn't equal 0. (x-3) equals 0 if x = 3. Since you're looking for the limit as x-> 0, and x is continuous at that point, you can directly plug in the 0 into the equation, getting: 2+(1/0-3)) = 2+ -1/3 = 5/3. So the limit as x-> 0 of the function is 5/3.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
yogirlkaylie: i took dis on thanksgiving
8 seconds ago 37 Replies 0 Medals
xaviera20: drip?
7 minutes ago 13 Replies 0 Medals
Jackalope: Which weighs more, a pound of feathers or a pound of bricks? no cheating
11 minutes ago 30 Replies 0 Medals
stormyfurr: What starts with a P and ends with an E and has a thousand letters?
21 minutes ago 8 Replies 0 Medals
dinonuggets12: anyone got a good camera app that i can use
27 minutes ago 1 Reply 0 Medals
Maddie2005: If eleven plus two equals one, what does nine plus five equal?
9 minutes ago 40 Replies 3 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!