I need help solving: One number is 4 more than another. IF 6 times the smaller minus 4 times the larger is 4, what are the two numbers.

We have simultaneous equations: \[ x = y + 4 \] and \[ 6y - 4x = 4 \]

Thanks gentoolx. Ok I get that, are they solved separately, or is one solved before the other?

So, you can just substitute the value from first equation (x value) to the second equation or you can transform the first to \[ x-y=4 \] and then: \[4x-4y=16\] Then you sum up these two equations to get \[2y = 20 \] Then you compute value of y and then you substitute it to one of the original equations to compute x.

To be clear: when I meant "these two equations" I meant transformed equation and the second equation from original ones.

Thanks again, I am sorry how do you get the 4 on the other side of the equal sign

you multiplied 4 by both sides

I multiplied both sides by four.

\[x = y + 4\] \[x - y = 4 | * 4\]\[4x - 4y = 16\]

More info about solving simultaneous equations here: http://en.wikipedia.org/wiki/Simultaneous_equations

Thanks so much for your help, I will try that website, its been a long time since I took algebra

You're welcome.

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