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OpenStudy (anonymous):
Solve equation: (d+2)(d-5)=-6
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OpenStudy (anonymous):
Can anyone help!!!
OpenStudy (anonymous):
i think its d^2 - 5d + 2d - 10 = -6 d^2-3d-10=-6 d^2-3d=4
OpenStudy (anonymous):
and d = -2 or d= 5
OpenStudy (sandra):
well, these are easier to solve if you expand them and then factor them back out once you have something that equals zero
OpenStudy (sandra):
so for example, if you use foil, you get:
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OpenStudy (sandra):
d^2 -5d + 2d -10 = -6
OpenStudy (sandra):
d^2 -3d -4 = 0
OpenStudy (sandra):
now that you have the right side equal to zero, you can factor back out
OpenStudy (sandra):
and get (d+1)(d-4) = 0
OpenStudy (sandra):
so once you have a factored left hand side that equals zero, you know that the solutions are the two values that make either of the left hand components zero
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OpenStudy (sandra):
since zero times anything is zero
OpenStudy (sandra):
so one of the solutions is d=-1
OpenStudy (sandra):
can you get the other now?
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