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Solve equation: (d+2)(d-5)=-6
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Can anyone help!!!
i think its d^2 - 5d + 2d - 10 = -6 d^2-3d-10=-6 d^2-3d=4
and d = -2 or d= 5
well, these are easier to solve if you expand them and then factor them back out once you have something that equals zero
so for example, if you use foil, you get:
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d^2 -5d + 2d -10 = -6
d^2 -3d -4 = 0
now that you have the right side equal to zero, you can factor back out
and get (d+1)(d-4) = 0
so once you have a factored left hand side that equals zero, you know that the solutions are the two values that make either of the left hand components zero
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since zero times anything is zero
so one of the solutions is d=-1
can you get the other now?
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