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Mathematics 98 Online
OpenStudy (anonymous):

what is the basic for the column space of the matrix (0 6 6 3) (1 2 1 1) (4 1-34) (1 3 2 0) and what is the "rank"?

OpenStudy (anonymous):

The matrix has row-reduced form of: (1 | 0 | -1 | 0 0 | 1 | 1 | 0 0 | 0 | 0 | 1 0 | 0 | 0 | 0) So you basically can swap the 4th column to the 3rd one to get echelon form. From that, it's obvious that the rank is 3 and one of the basis for the column space is the I_3, the identity matrix for 3 dimensions.

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