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OpenStudy (anonymous):
Help please! Could someone walk me through this one : ) (3x =1)^3/2 = 64
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OpenStudy (anonymous):
Is this 3x-1 or 3x+1 on the inside of the parentheses? (or neither?)
OpenStudy (anonymous):
oops.. +
OpenStudy (anonymous):
(3x+1)^3/2=64 3x+1=64^2/3=16 3x=15 x=5
OpenStudy (anonymous):
I can see how you did it in my head but on paper what do I do with the 3/2?
OpenStudy (anonymous):
You raise both sides of the equation to 2/3 to cancel it out on the left.
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OpenStudy (anonymous):
ok : )
OpenStudy (anonymous):
p.s. Thanks so much!!
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