Question

How do I solve this equation:
(2x)^2=x^2+36^2?

Answer 1

Meh, I just did the whole thing, but server crashed.. :P
Oh well, I'll do it again.
(2x)^2 = 4x^2
So you got
4x^2 = x^2+36^2
By subtracting x^2 on both sides you get:
3x^2 = 36^2
Take your calculator, and do 36^2, you'll get 1296
You now have:
3x^2 = 1296
Divide both sides by 3 gives:
x^2 = 432
Which gives
\[x = +- \sqrt{}\]

Answer 2

Ofcourse the server bugs again... Continuing where it failed:
Which gives:
x = +- squareroot of 432