Hi there, i was wondering if you could help me find the range of this function: 3ln(y + 4) = 2ln(x + 2) -2ln(x + 9) + 3ln(x^2 -1)
(range of values for x and y)
ok we see that we have ln (y+4) on the left side. so y+4 > 0 , since ln 0 or ln (negative) is not defined. so y > -4 for the range. for the domain we have x + 2 > 0 , x + 9 > 0 and x^2 -1 > 0 you take the intersection of these conditions. so x > -2 , x > -9, x > 1 or x < -1 . so the domain is (-2, -1) union (-1, oo)
please check work over
Thank you very much for your reply. i spent the whole day looking at it and i couldnt get my head around it. i was trying to gather the terms on the right hand side to simplify the function. guess i was looking at it the wrong way!
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