Question

Hi there, i was wondering if you could help me find the range of this function:

3ln(y + 4) = 2ln(x + 2) -2ln(x + 9) + 3ln(x^2 -1)

Answer 1

(range of values for x and y)

Answer 2

hello

Answer 3

ok we see that we have ln (y+4) on the left side. so y+4 > 0 , since ln 0 or ln (negative)
is not defined.
so y > -4 for the range.
for the domain we have x + 2 > 0 , x + 9 > 0 and x^2 -1 > 0
you take the intersection of these conditions.
so x > -2 , x > -9, x > 1 or x < -1 . so the domain is (-2, -1) union (-1, oo)

Answer 4

please check work over

Answer 5

Thank you very much for your reply. i spent the whole day looking at it and i couldnt get my head around it. i was trying to gather the terms on the right hand side to simplify the function. guess i was looking at it the wrong way!