Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

The altitude of a triangle is increasing at a rate of 2 centimeters/minute while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters?

OpenStudy (bahrom7893):

i really think you should practice related rates, working on your other problem right now

OpenStudy (anonymous):

hey

OpenStudy (bahrom7893):

hey will do this one later, i gotta eat

OpenStudy (anonymous):

carra?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

want me to solve it

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Area of triangle = 1/2 base * altitude

OpenStudy (anonymous):

area is changing with respect to time, base is changing with respect to time and altitude is changing with respect to time . so taking derivative we have

OpenStudy (anonymous):

product rule , which is complicated... ok lets look for a relationship given

OpenStudy (anonymous):

ok product rule it is

OpenStudy (anonymous):

dA/dt = 1/2 b * da/dt + 1/2 db/dt * a , where a is altitude

OpenStudy (anonymous):

b is base, A is area

OpenStudy (anonymous):

da/dt = 2 "The altitude of a triangle is increasing at a rate of 2 centimeters/minute " dA/dt = 3.5 "while the area of the triangle is increasing at a rate of 3.5 square centimeters/minute." At what rate is the base of the triangle changing when the altitude is 10 centimeters and the area is 95 square centimeters? what is db/dt , when a = 10 , and A= 95

OpenStudy (anonymous):

dA/dt = 1/2 b * da/dt + 1/2 db/dt * a we have to go back and solve for b here to find db/dt

OpenStudy (anonymous):

A = 1/2 * b*a, A = 95, a = 10, so b = 19 using algebra.

OpenStudy (anonymous):

A = 1/2 * b*a, A = 95, a = 10, so b = 19 using algebra.

OpenStudy (anonymous):

plug back into dA/dt = 1/2 b * da/dt + 1/2 db/dt * a 3.5 = 1/2 * 19 *2 + 1/2 * db/dt * 10 , and solve for db/dt

OpenStudy (bahrom7893):

http://i52.tinypic.com/263ww2c.jpg

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos: ik i'm late but finished ToT added some details :p
3 hours ago 2 Replies 0 Medals
Grimson: What's your new years resolution.
9 hours ago 1 Reply 1 Medal
LemmyluvsGelo: Why be sad when you could js be Gone . ud83dudd7a
8 hours ago 4 Replies 1 Medal
Ferrari: anyone have insta??
4 hours ago 23 Replies 3 Medals
xXAikoXx: I made art
13 hours ago 6 Replies 3 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!