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OpenStudy (anonymous):
there are 20 coins from antwerp and 16 from brussels. if a person chooses 5 of these coins at random what is the probability that 2 coins are from antwerp and 3 from brussels?
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OpenStudy (anonymous):
(20C2 x 16C3)/36C5... the C means combinations...you can choose 2 antwerp coins from 20 in 20C2 was...and you can choose 3 brussels coins out of 16 in 16C3... you can choose 5 coins out of 36 in 36C5 ways...your answer should be 0.2822...
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