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OpenStudy (anonymous):
Determine the convergence or divergence of the series. (2n)!/[(n-1)3^n]
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OpenStudy (anonymous):
Diverge, because n! has a higher order than b^n for any constant b.
OpenStudy (mathteacher1729):
Do you mean \[\frac{n!}{(n-1)3^n}\] or \[\frac{n!}{(n-1)^{3n}}\] ?
OpenStudy (mathteacher1729):
Either of those is sequence, not a series. A sequence effectively a list of numbers. A series tells you to "add up all the numbers in the sequence."
OpenStudy (anonymous):
Regardless of whether they're sequences or series, the nth terms don't converge anyway. I didn't notice the second interpretation. Hmm...
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