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y=ln(lnx) ? why?
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okay what's the question here?
whats the derivative?
oh u mean: y = ln(lnx); dy/dx - ?
yes i forgot the steps
sorry this place keeps crashing will have to retype
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y = Ln(Lnx) dy/dx = y' = [1 / Lnx] * [Lnx]' = [1 / Lnx] * [1/x] = 1/(x*Lnx)
dy/dx = 1 / (x*Lnx) <=ur answe
*answer
ok ty
np
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