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does anyone know how to find the derivative of e^2x/1+x?
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do you have a graphing calculator? if so, you can do it on there
no i do not, my teacher wont let us use one
T_T no i cant figure it out, sorry!
its okay
Use the quotient rule: \[\frac{d}{dx} (\frac{f(x)}{g(x)}) = \frac{g(x)*f'(x) - f(x)*g'(x)}{g(x)^{2}}\]
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Since you're given d/dx (\[\frac{e^{2x}}{1+x}\] \[f(x) = e^{2x} \ \ f'(x) = 2e^{2x} \ \ g(x) = 1+x \ \ g'(x) = 1\] Plug in and solve!
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