the perimeter of a rectagular calculator is 36cm the length is cm greater than the width. find the width and the length?
how many cm greater than the width is the length?
the lenght is 4cm perimeter is 36 cm
4cm greater than the width srry guys how about to write dwn the problem
Sorry, I lost my explanation. One sec.
Let : x = length y = width Think: perimeter = sum of the exterior sides of a particular polygon. Therefore, the perimeter of a rectangle = two lengths + two widths 2x + 2y = 36 ----- 1st equation We can make a second by looking at the 2nd half of the question. If the length is 4 cm greater than the width, the width is equal to the length - 4 cm. y = x - 4 ---- second equation
i just get confuse on how to write dwn the problem thanxs
Then we substitute one equation into the other to solve for one of the dimensions. For example, 2x + 2(x-4) = 36 4x -8 = 36 4x = 28 x = 7 cm Sub. x = 7 into either of the equations. y = 7 - 4 y = 3 cm
thanks so much!! i think i need to practice more on this type of explanations
No problem, word problems are often difficult for most students!
Gail trip cost 1.50 per trip(one way). montly pass cost $54 express as inequality the # of trips per month Gail should make if the pass is to save her money. I need to be able to write dwn and solve it.. help thanks.
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