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-1<(x^2)/2<1 , can anyone solve and give me the range for x??
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-1<(x^2)/2<1 -2<(x^2)<2 sqrt(-2)<x<sqrt(2)
so my range will be in complex number and it is 2i<x<(2^(1/2)) or we ignore the 2i and take -(2^(1/2))<x<(2^(1/2)) as the range
most teachers dont go into imaginary numbers i would just leave both my 2s underneath the square root symbol...
can you clarify this statement into an equation for the range..
\[\sqrt{-2}<x<\sqrt{2}\]
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ok dude... thx a lot :)
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