Question

Segment Addition: Can someone help me solve this problem? In a rowing race, the distance between the teams in first and second place is 5.7 meters. The distance between the teams in second and third place is one-third that
distance. How much farther ahead is the team in first place than the team in third?

Answer 1

Distance b/n 1st and 2nd: 5.7
Distance b/n 2nd and 3rd is 1/3 that, so : 5.7 * (1/3) = 1.9

Answer 2

Total distance:
5.7 + 1.9 = 13.3 <- Dis b/n 1 and 3

Answer 3

fan me if i helped, please

Answer 4

okay thanks! can you please explain to me how you got this answer? : )

Answer 5

Well you have given:
Distance b/n 1st and 2nd is 5.7 and distance between 2nd and 3rd is 1/3 of 5.7, which means divide 5.7 by 3

Answer 6

so distance b/n 2nd and 3rd is 5.7/3 = 1.9

Answer 7

so you multiply then divide?

Answer 8

or just divide?

Answer 9

So from 1 to 2 there is 5.7 and from 2 to 3 there is 1.9. Which means from 1 to 3 there is 5.7+1.9 = 7.6

Answer 10

no u just divide, and sorry my previous answer was a typo, its not 13.3, the answer is 7.6

Answer 11

hmm im totally confused : /

Answer 12

is this the first step --> 5.7 * (1/3) = 1.9 then you would add 5.7+1.9= 7.6?

Answer 13

& you get 7.6 as your answer?

Answer 14

yes

Answer 15

thank youuu! : )

Answer 16

np