Question

Find the solution to each system by the substitution method for these, 10x3y=8 and 2x+y=2.......also have so how to check your answers......so far i have 10x+3y=8, 10x=3y+8,2(3y+8)+y=8 6y+16+y=8, 7y+16=8, 7y=16+2 7y=18, y=2.5

Answer 1

x = 1/2 , y = 1

Answer 2

ok so what did i do wrong then

Answer 3

10x = 3y +8 is wrong..........

Answer 4

ok i dont get how that is wrong

Answer 5

negative sign

Answer 6

so would it be 10x=3y-8

Answer 7

10x+3y=8 then it become 10x = -3y+8 right?

Answer 8

ok

Answer 9

you want me explain all?

Answer 10

preferrably if you would

Answer 11

im not very good but i will try my best

Answer 12

10x+3y=8 and 2x+y=2
take 2x+y=2
to be
y =2-2x
then insert
y =2-2x into 10x+3y=8
10x+3(2-2x)=8
10x+6-6x=8
4x+6=8
4x=8-6
4x=2
x=2/4
x=1/2
then insert
x=1/2 into y =2-2x
y=2-2(1/2)
y=2-1
y=1

Answer 13

ok thank you!