Question

This is an exercise on one of the readings.

def password():
n=0
a=str(raw_input("Password:"))
b="bob123"
if a==b:
print "You have successfully logged in"
n=0
exit()
else:
n+1
print "Sorry your password was wrong"
if n==3:
print "You have been denied access"
exit()
password()

all i wanna know is how do i get it to not print the blank space(runtime error) before the raw_input/"password:"

Answer 1

I figured it out my ordering was wrong if someone knows why the order changed this please explain. I know it fixed it but I still don't understand why?

def password():
n=0
while n<3:
a=str(raw_input("Password:"))
b="bob123"
if a==b:
print "You have successfully logged in"
n=0
exit()
else:
n=n+1
print "Sorry your password was wrong"
if n==3:
print "You have been denied access"
exit()
password()

Answer 2

I'm not sure what you're asking here. There's nothing in the first example that would cause it to print a 'blank space'. The only difference is that one uses a while loop to only allow 3 errrors and the first example does not.

Answer 3

What the heck i ran it severely times yesterday and it kept printing a blank input space before it said 'password:' but now when i try it it's working fine. Thanks anyway.