Question

integrate e^(x^1/2) / x^(1/2) borns are 4 to 1

Answer 1

Let u = x^1/2.
Then du = (1/2)x^(-1/2) dx. So 2du = x^(-1/2) dx

Then you’d be integrating 2*e^u du from u = 1 to u = 2.