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OpenStudy (anonymous):
if cos(pi/4) is sqrt2/2 i thought sec(pi/4) is 2/sqrt 2,but its just sqrt 2 . can some one please explain.
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OpenStudy (bahrom7893):
Okay: \[2/\sqrt{2} = (\sqrt{2})^2/\sqrt{2} = \sqrt{?}\]
OpenStudy (bahrom7893):
sqrt(2), i meant lol not question mark
OpenStudy (anonymous):
2/sqrt(2) and sqrt(2) are the same. Just rationalize as bahrom did.
OpenStudy (anonymous):
oh i see so i have to rationalize it. thank you guys
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