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Simplify: (-a^2b div 2b^-1)^3
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((-a )^2 * b / 2b^-1 ))^3 \[-a^{2}timesb\] \[\div (2b)^{-1}\] whole tp the power of 3
as we know -a^2 = -a * -a = a^2 now, 2b^-1 = 1/2b so now e get a^2 * b/ 1/2b a^2 * b * 2b/1 (2(ab)^2 )^3 8(ab)^6 is the answer if there is any mistake pardon me for that
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