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√x + 2 = 2 then (x + 2)² =
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see this questions is following: first square both sides we get
\[(\sqrt{x}+2)^{2}p =2^{2}\]
p = 2sorry
ohk now we know (a+b)^2 = \[a^{2}+2ab +b ^{2}\]
\[hence, (\sqrt{x}^{2}+2(\sqrt{x}+2)+2^{2} = 4\]
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now we get \[x +2\sqrt{x}+4+4=4\]
\[x +2\sqrt{x} = 4\]
now we will solve (x=2)^2
\[x ^{2}+4x +4\]
i will continue my answer after some time i have to go seriously sorry
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