Question

how do you find critical number in calculus

Answer 1

\[\sqrt{2-x}\]

Answer 2

Take the derivative with respect to x, then find where the derivative is 0 or undefined

Answer 3

\[d/dx[\sqrt{2-x}] = -1/(2\sqrt{2-x})\]

Answer 4

The derivative can never be zero, so we need to next find if there is a point where it is undefined

Answer 5

in this case, at x = 2

Answer 6

This is a vertical tangent to the function

Answer 7

thanks