Question

Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 35 more than three times the largest number.

Answer 1

three consecutive numbers are x, x+1, and x+2. So that means:
2(x+x+1)=3(x+2)+35
4x+2=3x+41
x=39
39, 40, 41

Answer 2

thank you very much

Answer 3

pleasure. fan me?