Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

find all of the solutions of the following equation in the interval (0,2π). 2sinx-cscx=0

OpenStudy (anonymous):

2sinx - 1/sinx = 0 2sin^2(x) - 1 = 0 sin^2(x) = 1/2 sinx = (root2)/2 x = π/4, 3π/4

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!