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Mathematics 14 Online
OpenStudy (anonymous):

2nd derivative of x sin y=3

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

nevermind, the 3 is =3 not siny3, misread the problem

OpenStudy (anonymous):

[sinY (1+cos^2(y))]/(x^2)(cos^3(y))

OpenStudy (anonymous):

\[[sinY (1+\cos^2(y))]/(x^2)(\cos^3(y)) \]

OpenStudy (anonymous):

Thank you

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