Question

solve for x: log(10-3x)-2logx=0

Answer 1

log(10-3x) = 2logx
log(10-3x) = logx^2
10 - 3x = x^2
x^2 +3x -10 = 0
(x + 5)(x - 2) = 0
x = -5, 2
Eliminate the -5 because you can't take the logarithm of a negative number, and x = 2.

Answer 2

wow thx for explainin it i get it im doin review assigment so kinda forgot this stuff but its comin back thx