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Mathematics 18 Online
OpenStudy (anonymous):

evaluate using product, quotient chain sec(2theta)*tan^2(theta)

OpenStudy (anonymous):

sec 2 theta or sec^2 theta?

OpenStudy (anonymous):

\[\sec(2\theta)\tan^2(\theta)\]

OpenStudy (anonymous):

y'=sec {f(x)} = f'(x)sec(fx) tan f(x), for tan try splitting it into tan(x) tan(x)

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