Question

if log(x-3)+log(x+4) - logx = log 5 then what is the solution set

Answer 1

log[(x - 3)(x + 4)] - logx = log5
log(x^2 + x - 12) - logx = log5
log[(x^2 + x - 12)/x] = log 5
(x^2 + x - 12)/x = 5
x^2 + x - 12 = 5x
x ^2 - 4x - 12 = 0
(x + 2)(x - 6) = 0
x = -2, 6
Eliminate the -2
x = 6

Answer 2

did u factor in the begining

Answer 3

No, I multiplied with FOIL, which is the opposite of factoring. Try not to mix them up.

Answer 4

o ok thats wut i meeant

Answer 5

thx