Question

for which values of the parameter "a" thhe parabolas y=2x^2-ax+5 and y=x^2+4x-2a are tangent to each other? for each such "a" find the point of tangency

Answer 1

graph both functions, and find their point of tang ency, which is the one point the y "touch"

Answer 2

so i set them equal to each other then i put them to one side and set it =0 and solve for a?

Answer 3

YES

Answer 4

okay i dont thing this is right, but i got a=\[(x+1)(- x-5)\div2x\]