Question

write an equation of the line containing the given point & perpendicular to the given line. (0,6); 3x+7y=5

Answer 1

okey dokey, rewrite the equation in y = mx+b form

Answer 2

7y=5-3x
y = -3x/7 + 5/7

Answer 3

The slope is the coefficient of the x term, -3/7
The slope of the perpendicular line is the negative reciprocal. This means flip and negate the fraction.
The slope of the perpendicular line is thus 7/3

Answer 4

so the line will be:
y = 7/3(x-0)+6 = 7x/3 + 6