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ok so You roll one number cube twice. Find each probability. 1: P(1 and odd)
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How do i do this?
First find the probability of P(1), which is 1/6 Then find P(odd), which is 3/6 = 1/2
But how did u get 3/6?
Multiply the two probabilities together to find the probability they will happen in sequence. 1/6 * 1/2 = 1/12
Wait im Confused what am i Suppose to Rigth?
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I found 3/6 because there are 3 odd numbers out of 6 total
and 1/6 because there is one 1 and 6 total numbers on a die
the final answer is 1/12
so i write to answer it P(1/6x1/2=1/12?
P(1) = 1/6 P(odd) = 1/2 P(1)*P(odd) = 1/12
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Can uAlso Help me with this P(3 and even is the even 2?
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