Question

Having trouble factoring x^3 - 9x^2 + 27x - 27...I know the answer but don't know how to do it.

Answer 1

I used the "difference of cubes"... not sure if there's a easier way...
(x^3-27)-(9x^2-27x)
=(x-3)(x^2+3x+9)-9x(x-3)
=(x-3)(x^2+3x+9-9x)
=(x-3)(x^2-6x+9)
=(x-3)(x-3)(x-3)
=(x-3)^3

Answer 2

Thank you...that is very helpful. Wasn't thinking about re-grouping out of different order.