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The permeter of right triangle ABC is 132 Find the length of the hypotenuse .... AB is 4x+17 and CB (bottom line) 5x+5 and AC = x ???
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Okay so: P = 132 = AB + AC + CB = 4x + 17 + 5x + 5 + x
132 = 10x + 22
132-22 = 10x
110 = 10x; x = 11
So: AB = 44+17 = 61 CB = 55+5 = 60
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AC = 11
Hypothenuse is 61
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