A box contains the letters M I S S I S S I P P I. What is the probability of selecting an S first and a P second, if: a. the first letter is not replaced? b. the first letter is replaced.

Question

anonymous · Answer

4/11*2/10

anonymous · Answer

because there are 4 S out of 11 letters, there is 2 P out of the remaining 10 letters

anonymous · Answer

so the a. the first letter is not replaced what do i put?

anonymous · Answer

thus the number in the denominator goes from 11, the original number o letters in the word to 10, the remaining letters you can choose from

anonymous · Answer

so
what do i write????>?>

anonymous · Answer

4/11*2/10=8/110 which reduces to 4/55

anonymous · Answer

so that with the first letter not being replaced?

anonymous · Answer

yes, you leave the S out when you get ready to draw the 2nd time

anonymous · Answer

so the 2nd time on b. is the first letter is replaced what do i right

anonymous · Answer

then you take 4/11*2/11 since there is 11 letters on each draw

anonymous · Answer

so whats the answer?

anonymous · Answer

if the 1st letter is replaced the answer is 4/11*2/11 = 8/121

anonymous · Answer

Lols i really don't get this but ok can u explain clearly more about how u got all those Numbers