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factor 3xsquare+2x-8
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use quadratic equation
Actually use the AC method.
First multiply the first term by the last term (3)(8) = 24 Then find factors that multiply to get 24 and add to get 2. (-4)(6)
Then rewrite the equation using those two terms in place of the 2 3x^2 -4x + 6x = 8
factor 3 to the seconed power+2x-8
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the resuilt would be 2x-1
oops not 6x = 8 , 6x + 8
Once again.. I mean minus
umm were did they go
Then factor by grouping: (3x^2 -4x) + (6x - 8) x(3x-4) + 2(3x - 4)
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Then factor out the 3x - 4: (3x - 4)(x + 2) That will be your final answer
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