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find the derivative of the function at the given number f(x)=1-3x^2 at 2 i am confused i get -6xhsquared-6xh-h^2 all over h, plz help me
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f'(x) = -6x f'(2) = -18
-12
-18 was a typo.. PLEASE CLICK ON BECOME A FAN IF I HELPED! PLEASE!
btw where r u gettin h from?? Or was ur equation: (1-3x)^2 ?
can u post it properly?
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1-3xsquared
h is in derivative formula?
are you using [f(x + h) - f(x)]/h
but why?? u will use diff rules for different problems, this one is just f' = -6x
if you know the short cut, but if you don't you use the formula
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oh is he doin the limit definition?
i think so
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