Question

How do you solve 5x^2 = 2x +1 by completing the square?

Answer 1

firs move everything to the left:
5x^2 - 2x -1 = 0

Answer 2

okay

Answer 3

divide everything by 5

Answer 4

2x^2-5x-3 = 0
(2x + 1)(x - 3) = 0

x = -1/2 or x = 3

Answer 5

x^2 - (2/5)x - 1/5 = 0

Answer 6

So now u have the form of
x^2 - 2ax +a^2, and ur a = 1/5

Answer 7

i already have the answer i just cant seem to get the answer

Answer 8

5x^2 - 2x - a^2 +a^2 - 1 = 0
5x^2 - 2x - 1/25 + 1/25 - 1 = 0

Answer 9

rewrite:
sorry the 5s in front of x shouldnt be there

Answer 10

x^2 - 2x - a^2 +a^2 - 1 = 0
x^2 - 2x - 1/25 + 1/25 - 1 = 0
x^2 - 2x + 1/25 - 1/25 - 1 = 0

Answer 11

?????????

Answer 12

okay now what

Answer 13

i got some thing diff whow did you get that

Answer 14

what the heck, now i forgot the 5s, ughh sorry lets start over..

Answer 15

ahaa would it help if you had the answers

Answer 16

no, i know them, i just hate typin out math solutions

Answer 17

it says in the book that the answer is x+ 1/5 plus or minus the square root od 5/2

Answer 18

please :)

Answer 19

5x^2 - 2x -1 = 0
x^2 - (2/5)x + 1/5 = 0
x^2 - (2/5)x + 1/25 - 1/25 + 1/5 = 0

Answer 20

2x^2-5x-3 = 0
(2x + 1)(x - 3) = 0

x = -1/2 or x = 3

Answer 21

x^2 - 2 (1/5) x + (1/5)^2 - 1/25 + 1/5

Answer 22

that is what i got but i can be wrong

Answer 23

ur copying the wrong question dkglenn, stop confusing us

Answer 24

dkglenn ur wrong sorry

Answer 25

oh ok

Answer 26

so:
x^2 - 2 (1/5) x + (1/5)^2 - 1/25 + 1/5 = 0

Answer 27

see u have to recognize that:
x^2 - 2 (1/5) x + (1/5)^2 is the same as:
(x - 1/5)^2

Answer 28

ok

Answer 29

(x - 1/5)^2 - 1/25 + 1/5 = 0
(x - 1/5)^2 = 1/25 - 1/5

Answer 30

wait smth went wrong lemme check my arithmetic

Answer 31

mkayy

Answer 32

ive done the problem 5 diff times..so stressed so thanks for trying

Answer 33

okay so let me post the problem over again, thread is too long

Answer 34

mkay