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Mathematics 19 Online
OpenStudy (anonymous):

∫1/x(1+x^2 ) ⅆx

OpenStudy (bahrom7893):

use partial fractions: A/x + B/(1+x^2) = 1

OpenStudy (bahrom7893):

A + Ax^2 + Bx = 1 .... hmmm doesnt work does it

OpenStudy (bahrom7893):

wait lets try again: \[\int\limits_{}^{}1/[x(1+x^2)]dx = \int\limits_{}^{}xdx/[x^2(1+x^2)]\] Let u = x^2, du= 2x dx

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