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Write out the first three terms and the last term of ∑(-2i+6) (on top of the sigma sign is 40 and on the bottom i=1) . Use the formula for the sum of the first n terms of an arithmetic sequence find the sum.
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\[\sum_{i=1}^{40}(-2i+6)\]?
yes thats how the equation looks
first three term (-2(1)+6)+(-2(2)+6)+(-2(3)+6)
last three term same thing start from 38, 39,40
thank you I really appreciate the help
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Do you need help with arithemtic sum? Also if I helped you some way, please fan me
I understand arithmetic sum now thanks to you help but I do need help with another problem.
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